Hi,
I have attached the script.Initially your button should be inactive in hierarchy. Now on clicking mouse it will get active on screen. `using
using UnityEngine;
using UnityEngine.UI;
using System.Collections;
public class asdf : MonoBehaviour {
public GameObject abc;//Its your button
// Use this for initialization
void Start () {
}
// Update is called once per frame
void Update ()
{
if(Input.GetMouseButtonDown(0))
{
Debug.Log("Pressed left click.");
abc.SetActive(true);
}
}
}
Hope this will help you. You can place the code in start as per your need.
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